500Q^(-1/2)=4Q

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Solution for 500Q^(-1/2)=4Q equation:


D( Q )

Q < 0

Q = 0

Q < 0

Q = 0

Q = 0

Q in (0:+oo)

500*Q^(-1/2) = 4*Q // - 4*Q

500*Q^(-1/2)-(4*Q) = 0

500*Q^(-1/2)-4*Q = 0

t_1 = Q^(1/2)

500*t_1^-1-4*t_1^2 = 0

(500*t_1^0-4*t_1^3)/(t_1^1) = 0 // * t_1^2

t_1^1*(500*t_1^0-4*t_1^3) = 0

t_1^1

500-4*t_1^3 = 0

{ 1, -1, 2, -2, 4, -4, 5, -5, 10, -10, 20, -20, 25, -25, 50, -50, 100, -100, 125, -125, 250, -250, 500, -500 }

1

t_1 = 1

500-4*t_1^3 = 496

1

-1

t_1 = -1

500-4*t_1^3 = 504

-1

2

t_1 = 2

500-4*t_1^3 = 468

2

-2

t_1 = -2

500-4*t_1^3 = 532

-2

4

t_1 = 4

500-4*t_1^3 = 244

4

-4

t_1 = -4

500-4*t_1^3 = 756

-4

5

t_1 = 5

500-4*t_1^3 = 0

5

t_1-5

-4*t_1^2-20*t_1-100

500-4*t_1^3

t_1-5

4*t_1^3-20*t_1^2

500-20*t_1^2

20*t_1^2-100*t_1

500-100*t_1

100*t_1-500

0

-4*t_1^2-20*t_1-100 = 0

DELTA = (-20)^2-(-100*(-4)*4)

DELTA = -1200

DELTA < 0

t_1 in { 5}

t_1 = 5

Q^(1/2)-5 = 0

1*Q^(1/2) = 5 // : 1

Q^(1/2) = 5

Q^(1/2) = 5 // ^ 2

Q = 25

Q = 25

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